Fix --no-daemonize flag for synctl

code_spécifique_watcha
Erik Johnston 5 years ago
parent b4914681a5
commit 9ceb4f0889
  1. 12
      synctl

@ -150,8 +150,9 @@ def main():
parser.add_argument(
"--no-daemonize",
action="store_false",
dest="daemonize",
help="Run synapse in the foreground for debugging. "
"Will work only if the daemonize option is not set in the config."
"Will work only if the daemonize option is not set in the config.",
)
options = parser.parse_args()
@ -159,7 +160,7 @@ def main():
if options.worker and options.all_processes:
write('Cannot use "--worker" with "--all-processes"', stream=sys.stderr)
sys.exit(1)
if options.no_daemonize and options.all_processes:
if not options.daemonize and options.all_processes:
write('Cannot use "--no-daemonize" with "--all-processes"', stream=sys.stderr)
sys.exit(1)
@ -169,9 +170,8 @@ def main():
write(
"No config file found\n"
"To generate a config file, run '%s -c %s --generate-config"
" --server-name=<server name> --report-stats=<yes/no>'\n" % (
" ".join(SYNAPSE), options.configfile,
),
" --server-name=<server name> --report-stats=<yes/no>'\n"
% (" ".join(SYNAPSE), options.configfile),
stream=sys.stderr,
)
sys.exit(1)
@ -289,7 +289,7 @@ def main():
# Check if synapse is already running
if os.path.exists(pidfile) and pid_running(int(open(pidfile).read())):
abort("synapse.app.homeserver already running")
start(configfile, bool(options.no_daemonize))
start(configfile, bool(options.daemonize))
for worker in workers:
env = os.environ.copy()

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