Stabilize regression test from c0962a113.

Per buildfarm.

Co-authored-by: Alena Rybakina <a.rybakina@postgrespro.ru>
Co-authored-by: Tom Lane <tgl@sss.pgh.pa.us>
Discussion: https://postgr.es/m/srnuqlttuimzmvoulhsrbgvj4vnul6b65osswvua7sfkqsvmuy@yg7apybpxp34
pull/210/head
Tom Lane 5 months ago
parent 64e7fa43a9
commit 3ba2cdaa45
  1. 37
      src/test/regress/expected/subselect.out
  2. 8
      src/test/regress/sql/subselect.sql

@ -2755,28 +2755,29 @@ SELECT * from onek WHERE unique1 in (VALUES(1200::bigint), (1));
-- VtA shouldn't depend on the side of the join probing with the VALUES expression.
EXPLAIN (COSTS OFF)
SELECT c.oid,c.relname FROM pg_class c JOIN pg_am a USING (oid)
WHERE a.oid IN (VALUES (1), (2));
QUERY PLAN
---------------------------------------------------------
Nested Loop
-> Seq Scan on pg_am a
Filter: (oid = ANY ('{1,2}'::oid[]))
-> Index Scan using pg_class_oid_index on pg_class c
Index Cond: (oid = a.oid)
(5 rows)
SELECT c.unique1,c.ten FROM tenk1 c JOIN onek a USING (ten)
WHERE a.ten IN (VALUES (1), (2));
QUERY PLAN
--------------------------------------------------
Hash Join
Hash Cond: (a.ten = c.ten)
-> Seq Scan on onek a
Filter: (ten = ANY ('{1,2}'::integer[]))
-> Hash
-> Seq Scan on tenk1 c
(6 rows)
EXPLAIN (COSTS OFF)
SELECT c.oid,c.relname FROM pg_class c JOIN pg_am a USING (oid)
WHERE c.oid IN (VALUES (1), (2));
QUERY PLAN
---------------------------------------------------------------
SELECT c.unique1,c.ten FROM tenk1 c JOIN onek a USING (ten)
WHERE c.ten IN (VALUES (1), (2));
QUERY PLAN
--------------------------------------------------
Hash Join
Hash Cond: (a.oid = c.oid)
-> Seq Scan on pg_am a
Hash Cond: (c.ten = a.ten)
-> Seq Scan on tenk1 c
Filter: (ten = ANY ('{1,2}'::integer[]))
-> Hash
-> Index Scan using pg_class_oid_index on pg_class c
Index Cond: (oid = ANY ('{1,2}'::oid[]))
-> Seq Scan on onek a
(6 rows)
-- Constant expressions are simplified

@ -1243,11 +1243,11 @@ SELECT * from onek WHERE unique1 in (VALUES(1200::bigint), (1));
-- VtA shouldn't depend on the side of the join probing with the VALUES expression.
EXPLAIN (COSTS OFF)
SELECT c.oid,c.relname FROM pg_class c JOIN pg_am a USING (oid)
WHERE a.oid IN (VALUES (1), (2));
SELECT c.unique1,c.ten FROM tenk1 c JOIN onek a USING (ten)
WHERE a.ten IN (VALUES (1), (2));
EXPLAIN (COSTS OFF)
SELECT c.oid,c.relname FROM pg_class c JOIN pg_am a USING (oid)
WHERE c.oid IN (VALUES (1), (2));
SELECT c.unique1,c.ten FROM tenk1 c JOIN onek a USING (ten)
WHERE c.ten IN (VALUES (1), (2));
-- Constant expressions are simplified
EXPLAIN (COSTS OFF)

Loading…
Cancel
Save